Succimer

Question: What minimum mass of succimer(in) is needed to bind all of the lead in a patient's bloodstream? What minimum mass of succimer (in ) is needed to bind all of the lead in a patient's bloodstream? Assume that patient blood lead levels are 38 , that total blood volume is 5.0 , and that one mole of succimer (C4H6O4S2) binds one mole of lead. Please help asap!

Answer: answer is in milligrams....

Question: What minimum mass of succimer (C4H6O4S2)(in mg) is needed to bind all of the lead in a patient's bloodstream? Assume that patient blood lead levels are .0004 g/L , that total blood volume is 5.0 L, and that one mole of succimer binds one mole of lead.

Answer: You will have: 0.0004*5 = 0.002g lead Molar mass lead = 207.2g/mol 0.002g = 0.002/207.2 = 9.65*10^-6 mol Pb Therefore you will need 9.65*10^-6 mol succimer Molar mass succimer = 12.011*4 + 1.008*6 + 15.999*4 + 32.066*2 = 182.22g/mol 9.65*10^-6 mol = 182.22*9.65*10^-6 = 1.75*10-3 g 1g = 10^3mg required dose = 1.75mg succinate

Question: mass of succimer needed? i've been trying this problem like crazy and i can't get the answer right. patient blood lead levels are 33 nanograms/dL, the total blood volume is 5L. one mole of lead = one mole of succimer, how much succimer (molar mass - 182.2g) in mg do you need to combat the lead? i keep getting 1.45 x 10^-3 mg, but apparently it's not right.. help!

Answer: The patient has 33 ng of Pb per deciliter of blood. So the total Pb in the blood is 33ng/dL (5L) (10dL/1L) = 1650 ng Pb. Conversion to moles yields: 1650 x10^-9 g Pb (1 mol/207.2 g) = 7.96 x 10^-9 mol Pb, which means you need 7.96 x 10^-9 mol sucicmer. Conversion back to grams (mass of succimer) yields: 7.96 x 10^-9 mol succimer (182.2g/1 mol) (1000 mg/1g) = 1.45E-3 mg. I am getting the same number you are. Is there any more information in the problem? For example, does it just say lead or does it mention a lead compound (If it's grams of a compound then there might be less lead than the calculation)?

Question: CHEMISTRY HELP COLLEGE CHEM SUPER HARD? Lead poisoning is a serious condition resulting from the ingestion of lead in food, water, or other environmental sources. It affects the central nervous system, leading to a variety of symptoms such as distractibility, lethargy, and loss of motor coordination. Lead poisoning is treated with chelating agents, substances that bind to metal ions, allowing it to be eliminated in the urine. A modern chelating agent used for this purpose is succimer (C4H6O4S2). Suppose you are trying to determine the appropriate dose for succimer treatment of lead poisoning. What minimum mass of succimer (in mg) is needed to bind all of the lead in a patient's bloodstream? Assume that patient blood lead levels are 26 ug/dl , that total blood volume is 5.0 L, and that one mole of succimer binds one mole of lead.

Answer: Let blood be called B. Let succimer be called S. Atomic weights: Pb=207, C=12, H=1, O=16, S=32, C4H6O4S2=182 5.0LB x 10dLB/1LB x 26ugPb/1dLB x 1gPb/(1x10^6ugPb) x 1molPb/207gPb x 1molS/1molS x 182gS/1molS x 1000mgS/1gS = 1.14 mg succimer

Question: Help with Chemistry problem; don't want answer just how to start? I don't want the answer, I'm just having a difficult time starting the problem. Please help. The question is: Determine the appropriate dose for succimer (C4H6O4S2) treatment for lead poisoning. What minimum mass of succimer in milligrams is needed to bind all of the lead in a patient's blood stream? Assume that patient blood lead levels are 0.550 mg/L, that total blood volume is 5.0 L, and that 1 mol of succimer binds 1 mol of lead. What ratios would I set up? How would I start this? Thank you for your help!

Answer: first, calculate how many moles of lead are in the patient's blood stream. (conver mg/L to mg to grams to moles) Then convert the answer to moles of succimer; its a 1:1 ratio so the moles of succimer will be same as the moles of lead. Then convert moles of succimer to mg of succimer and you have your answer! good luck. hope this helps.

Question: What minimum mass of succimer is needed to bind all of the lead in a patient's bloodstream? What minimum mass of succimer C4H6O4S2 (in mg) is needed to bind all of the lead in a patient's bloodstream? Assume that patient blood lead levels are 28 mirrograms/deci Liters, that total blood volume is 5.0 L, and that one mole of succimer binds one mole of lead.

Answer: 28 micrograms/deciLiters 1st u need to convert deciliters to Liters. Lead is 207.2 grams per mole. Then you need to convert 28 micrograms Lead into moles. Find the Molec weight of the Succimer. then you'll be on your way..

Question: Please, I need help again? Lead poisoning is treated with chelating agents. A very effective chelating agent is succimer. C4H6O4S2. What is the minimum mass of succimer in milligrams needed to bind all of the lead in a patient’s bloodstream? Assume the patients blood lead level is 0.55 milligrams/liter that total blood volume is 8.o liters and that 1 mole of succimer binds 1 mole of lead (pb, atomic mass =207.2 amu) please what is the answer and what is the formula to arrive at an answer

Answer: In order to find out how many milligrams of succimer are needed, we need to find the molar mass of succimer and the number of moles of lead in the blood. So, the amount of lead in the blood is 0.55 mg/L and there are 8 L of blood, so there are 4.4 mg of Pb in the blood. The molar mass of lead is 207.2 g/mol, which is 207,200 mg/mol. 4.4 mg of Pb divided by 207,200 mg/mol gives us 2.12E-5 mol of Pb. Since the ratio of succimer to Pb is 1:1, there need to be 2.12E-5 mol of succimer. Now the molar mass of succimer is 182.22 g/mol (added molar masses of all the components). Now 2.12E-5 mol times 182.22 g/mol gives us 0.00387 g of succimer, which is 3.87 mg. So the final answer, with significant figures taken into account, is 3.9 mg of succimer.

Question: CHEMISTRY HELP COLLEGE CHEM SUPER HARD? Lead poisoning is a serious condition resulting from the ingestion of lead in food, water, or other environmental sources. It affects the central nervous system, leading to a variety of symptoms such as distractibility, lethargy, and loss of motor coordination. Lead poisoning is treated with chelating agents, substances that bind to metal ions, allowing it to be eliminated in the urine. A modern chelating agent used for this purpose is succimer C4 H6 O4 S2 ). Suppose you are trying to determine the appropriate dose for succimer treatment of lead poisoning. What minimum mass of succimer in mg is needed to bind all of the lead in a patient's bloodstream? Assume that patient blood lead levels are 33 ug/dL, that total blood volume is 5.0 L, and that one mole of succimer binds one mole of lead. Hey, guys thanks for the help, but 1.45 doesnt seem like the right answer, i plugged it in and says incorrect answer, please i need the right response. I ONLY HAVE 1 ATTEMPT REMAINING!!! thank you TURNS OUT I HAD TO ROUND TO 1.5 thank you sooooo much, i will pick you as best answer, when it allows me.

Answer: mass of lead (ug =10-6g): 33x10^-6 g/dL(10 dL/L) 5L= 1.65x10-^5 g moles lead 1.65x10-^3 g/207g/mole= 7.97x10^-6mole moles lead = moles succimer. molar mass succimer 4(12)+6(1)+ 4(16) + 2(32)= 182 g/mole 7.97x10^-6moles (182 g/mole)= 1.45x10-3 g= 1.45 mg succimer

Question: CHEMISTRY HELP COLLEGE CHEM SUPER HARD? Lead poisoning is a serious condition resulting from the ingestion of lead in food, water, or other environmental sources. It affects the central nervous system, leading to a variety of symptoms such as distractibility, lethargy, and loss of motor coordination. Lead poisoning is treated with chelating agents, substances that bind to metal ions, allowing it to be eliminated in the urine. A modern chelating agent used for this purpose is succimer (C4 H6 O4 S2 ). Suppose you are trying to determine the appropriate dose for succimer treatment of lead poisoning. What minimum mass of succimer in mg is needed to bind all of the lead in a patient's bloodstream? Assume that patient blood lead levels are 34 ug/dL, that total blood volume is 5.0 L, and that one mole of succimer binds one mole of lead

Answer: 5.0 L x (10 dL/L) x (34 ug of Pb/dL) / (1000000ug/g) / (207.2100 g/mol of Pb) x (1 mol Pb/ 1 mol succimer) x (182.2195 g/mol succimer) x (1000 mg/g) = 1.5 mg succimer

Question: How do you solve this problem? What minimum mass of (C4H6O4S2) succimer (in mg ) is needed to bind all of the lead in a patient's bloodstream? Assume that patient blood lead levels are 45 ug/dL , that total blood volume is 5.0 , and that one mole of succimer binds one mole of lead. Any help is appreciated...

Answer: 5.0 L x (10 dL/L) x (45 ug of Pb/dL) / (1000000ug/g) / (207.2100 g/mol of Pb) x (1 mol Pb/ 1 mol succimer) x (182.2195 g/mol succimer) x (1000 mg/g) = 2.0 mg succimer

Question: What minimum mass of succimer C4H6O4S2 (in mg) is needed to bind all of the lead in a patient's bloodstream? What minimum mass of succimer is needed to bind all of the lead in a patient's bloodstream? What minimum mass of succimer C4H6O4S2 (in mg) is needed to bind all of the lead in a patient's bloodstream? Assume that patient blood lead levels are 27 mirrograms/deci Liters, that total blood volume is 5.0 L, and that one mole of succimer binds one mole of lead. please explain how you found the answer, thanks!

Answer: Just count your carbs as usual .

Question: Chemistry:What minimum mass of succimer (in mg ) is needed to bind all of the lead in a patient's bloodstream? Lead poisoning is a serious condition resulting from the ingestion of lead in food, water, or other environmental sources. It affects the central nervous system, leading to a variety of symptoms such as distractibility, lethargy, and loss of motor coordination. Lead poisoning is treated with chelating agents, substances that bind to metal ions, allowing it to be eliminated in the urine. A modern chelating agent used for this purpose is succimer (C4H6O4S2). Suppose you are trying to determine the appropriate dose for succimer treatment of lead poisoning. What minimum mass of succimer (in mg ) is needed to bind all of the lead in a patient's bloodstream? Assume that patient blood lead levels are 51 ug/dl , that total blood volume is 5.0 L , and that one mole of succimer binds one mole of lead.

Answer: (5.0 L) x (0.00051 g/L) / (207.2100 g Pb/mol) x (1/1) x (182.2195 g C4H6O4S2/mol) = 0.0022 g = 2.2 mg C4H6O4S2

Question: What minimum mass of succimer (in ml) is needed to bind all of the lead in a patient's bloodstream? Assume that patient blood lead levels are 55 μg/dl , that total blood volume is 5.0 , and that one mole of succimer binds one mole of lead. What minimum mass of succimer (in ml) is needed to bind all of the lead in a patient's bloodstream? Assume that patient blood lead levels are 55 μg/dl , that total blood volume is 5.0 , and that one mole of succimer binds one mole of lead.

Answer: I don't think Professor Siegel would be very happy with you young lady